15 / MARCH / 2021
MATHEMATICS
MATHEMATICS
NOW WATCH THIS VIDEO FOR YOUR BETTER UNDERSTANDING:
NOW WATCH THIS VIDEO FOR YOUR BETTER UNDERSTANDING:
THOSE SHAPES WHICH HAVE LENGTH, BREADTH AND HEIGHT ARE KNOWN AS 3D SHAPES. THESE INCLUDES CUBE, CUBOID, SPHERE, CYLINDER AND CONE.
CUBOID :
A CUBOID HAS 6 PLANE SURFACES CALLED ITS FACES. THEY ALL ARE RECTANGLES. IT HAS 12 EDGES AND 8 CORNERS OR VERTICES.
THE OPPOSITE SURFACES OF A CUBOID ARE IDENTICAL.CUBE :A CUBE ALSO HAS 6 PLANE SURFACES CALLED ITS FACES. THEY ALL ARE SQUARES. IT HAS 12 EDGES AND 8 VERTICES.
ALL THE SURFACES OF A CUBE ARE IDENTICAL.DISTINCTION BETWEEN A CUBE AND A CUBOIDIN THE CASE OF A CUBOID, THE OPPOSITE FACES ARE IDENTICAL AND THEY MAY NOT BE SQUARES WHEREAS IN THE CASE OF CUBE ALL THE FACES ARE IDENTICAL (THEY ARE SQUARES).
CYLINDER :A CYLINDER HAS TWO PLANE FACES, TOP AND BASE. IT HAS ONE CURVED FACE. IT HAS TWO EDGES WHERE THE CURVED FACE MEETS ITS PLANE FACES. IT HAS NO VERTEX. THE BASE AND TOP OF A CYLINDER ARE OF THE SAME SHAPE AND SIZE.
CONE:A CONE HAS ONLY ONE PLANE FACE (ITS BASE) AND ONLY ONE CURVED FACE. IT HAS ONE VERTEX. IT HAS ONE EDGE WHERE THE CURVED FACE MEETS THE PLANE FACE.
SPHERE:IT HAS ONLY ONE CURVED FACE. IT DOES NOT HAVE ANY VERTEX OR EDGE.
ASSIGNMENT:- COMPLETE THE FOLLOWING IN YOUR MATHEMATICS-OCB.MATHEMATICS BOOK, PG NO.206, EX NO. 15 B, DO NO.1 TO 4.
THOSE SHAPES WHICH HAVE LENGTH, BREADTH AND HEIGHT ARE KNOWN AS 3D SHAPES. THESE INCLUDES CUBE, CUBOID, SPHERE, CYLINDER AND CONE.
CUBOID :
A CUBOID HAS 6 PLANE SURFACES CALLED ITS FACES. THEY ALL ARE RECTANGLES. IT HAS 12 EDGES AND 8 CORNERS OR VERTICES.
THE OPPOSITE SURFACES OF A CUBOID ARE IDENTICAL.
CUBE :
A CUBE ALSO HAS 6 PLANE SURFACES CALLED ITS FACES. THEY ALL ARE SQUARES. IT HAS 12 EDGES AND 8 VERTICES.
ALL THE SURFACES OF A CUBE ARE IDENTICAL.
DISTINCTION BETWEEN A CUBE AND A CUBOID
IN THE CASE OF A CUBOID, THE OPPOSITE FACES ARE IDENTICAL AND THEY MAY NOT BE SQUARES WHEREAS IN THE CASE OF CUBE ALL THE FACES ARE IDENTICAL (THEY ARE SQUARES).
CYLINDER :
A CYLINDER HAS TWO PLANE FACES, TOP AND BASE. IT HAS ONE CURVED FACE. IT HAS TWO EDGES WHERE THE CURVED FACE MEETS ITS PLANE FACES. IT HAS NO VERTEX. THE BASE AND TOP OF A CYLINDER ARE OF THE SAME SHAPE AND SIZE.
CONE:
A CONE HAS ONLY ONE PLANE FACE (ITS BASE) AND ONLY ONE CURVED FACE. IT HAS ONE VERTEX. IT HAS ONE EDGE WHERE THE CURVED FACE MEETS THE PLANE FACE.
SPHERE:
IT HAS ONLY ONE CURVED FACE. IT DOES NOT HAVE ANY VERTEX OR EDGE.
05 / MARCH / 2021
MATHEMATICS
MATHEMATICS
COMMON SOLIDSNOW WATCH THIS VIDEO FOR BETTER UNDERSTANDING:
A SATELLITE MOVES IN SPACE. THE MOON ALSO MOVES IN SPACE. OUR EARTH ALSO MOVES IN SPACE.
WE WALK ON THE GROUND. WE SWIM ALONG THE LENGTH AND BREADTH OF A SWIMMING POOL. WHEN WE JUMP FROM THE DIVING BOARD, WE ALSO MOVE IN SPACE.
WE CAN SHOW A RECTANGLE, A TRIANGLE, A SQUARE OR A CIRCLE ON A PLANE PAPER. BUT WE CANNOT DRAW FOOTBALL, A TENNIS BALL, A MATCH BOX, A TIN OF GHEE, ETC., ON THE PLANE PAPER. AT THE MOST WE CAN REPRESENT THE FOOTBALL BY A CIRCLE.
SUCH BODIES ARE CALLED SOLIDS. THEY OCCUPY SPACE.
EACH OF THE OBJECTS GIVEN BELOW HAS THE SHAPE OF CUBOID.
EACH OF THE OBJECTS GIVEN BELOW HAS THE SHAPE OF A SPHERE.
EACH OF THE OBJECTS GIVEN BELOW HAS THE SHAPE OF A CONE.
PLANE AND CURVED SURFACESEACH SOLID OCCUPIES SPACE. THE PART OF THE SOLID WHICH WE USUALLY SEE AND TOUCH IS CALLED SURFACE OF THE SOLID.
A. LOOK AT THE SURFACES OF THE OBJECTS SHOWN BELOW :
SOME SOLIDS HAVE ONLY PLANE SURFACE(S) AND SOME HAVE ONLY CURVED SURFACE WHILE SOME HAVE BOTH PLANE AND CURVED SURFACES AS WELL.
THE ABOVE OBJECTS HAVE ONLY PLANE SURFACE.
B. LOOK AT THE SURFACES OF THE OBJECTS SHOWN BELOW :
THE ABOVE OBJECTS HAVE ONLY CURVED SURFACE.
C. LOOK AT THE SURFACES OF THE OBJECTS SHOWN BELOW :
THE ABOVE OBJECTS HAVE BOTH PLANE AS WELL AS CURVED SURFACES.
COMMON SOLIDS
CUBOID : A CUBOID HAS 6 PLANE SURFACES CALLED ITS FACES. THEY ALL ARE RECTANGLES. IT HAS 12 EDGES AND 8 CORNERS OR VERTICES.
THE OPPOSITE SURFACES OF A CUBOID ARE IDENTICAL.
CUBE : A CUBE ALSO HAS 6 PLANE SURFACES CALLED ITS FACES. THEY ALL ARE SQUARES. IT HAS 12 EDGES AND 8 VERTICES. ALL THE SURFACES OF A CUBE ARE IDENTICAL.
DISTINCTION BETWEEN A CUBE AND A CUBOID
IN THE CASE OF A CUBOID, THE OPPOSITE FACES ARE IDENTICAL AND THEY MAY NOT BE SQUARES WHEREAS IN THE CASE OF CUBE ALL THE FACES ARE IDENTICAL (THEY ARE SQUARES).
CYLINDER : A CYLINDER HAS TWO PLANE FACES, ITS TOP AND BASE. IT HAS ONE CURVED FACE. IT HAS TWO EDGES WHERE THE CURVED FACE MEETS ITS PLANE FACES. IT HAS NO VERTEX.
THE BASE AND TOP OF A CYLINDER ARE OF THE SAME SHAPE AND SIZE.
CONE : A CONE HAS ONLY ONE PLANE FACE (ITS BASE) AND ONLY ONE CURVED FACE. IT HAS ONE VERTEX. IT HAS ONE EDGE WHERE THE CURVED FACE MEETS THE PLANE FACE.
SPHERE : IT HAS ONLY ONE CURVED FACE. IT DOES NOT HAVE ANY VERTEX OR EDGE.
SOLID FIGURECUBE, CUBOID, CYLINDER, SPHERE, ETC., ARE CALLED SOLID FIGURES. LET'S TRY TO ANSWER OURSELVES.
A. A CUBE HAS............CORNERS.
B. A CUBE HAS............EDGES.
C. A CUBE HAS............SQUARE FACES.
A. A CUBOID HAS............CORNERS.
B. A CUBOID HAS............EDGES.
C. A CUBOID HAS............RECTANGULAR FACES.
A. A CYLINDER HAS............CIRCULAR FACES.
B. A CYLINDER HAS............CURVED SURFACE.
A. A SPHERE HAS............CURVED SURFACE.
A. A CONE HAS............CIRCULAR FACES.
B. A CONE HAS............CURVED SURFACE.
C. A CONE HAS............CORNER.
ASSIGNMENT:- COMPLETE THE FOLLOWING IN YOUR MATHEMATICS-OCB.MATHEMATICS BOOK, PG NO. 204, EX NO. 15 A,DO NO. 1 TO 3 AND DRAW THE SHAPES OF CUBE, CUBOID, CONE, CYLINDER AND SPHERE FROM PG NO. 202.
A SATELLITE MOVES IN SPACE. THE MOON ALSO MOVES IN SPACE. OUR EARTH ALSO MOVES IN SPACE.
WE WALK ON THE GROUND. WE SWIM ALONG THE LENGTH AND BREADTH OF A SWIMMING POOL. WHEN WE JUMP FROM THE DIVING BOARD, WE ALSO MOVE IN SPACE.
WE CAN SHOW A RECTANGLE, A TRIANGLE, A SQUARE OR A CIRCLE ON A PLANE PAPER. BUT WE CANNOT DRAW FOOTBALL, A TENNIS BALL, A MATCH BOX, A TIN OF GHEE, ETC., ON THE PLANE PAPER. AT THE MOST WE CAN REPRESENT THE FOOTBALL BY A CIRCLE.
SUCH BODIES ARE CALLED SOLIDS. THEY OCCUPY SPACE.
EACH OF THE OBJECTS GIVEN BELOW HAS THE SHAPE OF CUBOID.
EACH OF THE OBJECTS GIVEN BELOW HAS THE SHAPE OF CUBOID.
EACH OF THE OBJECTS GIVEN BELOW HAS THE SHAPE OF A SPHERE.
EACH OF THE OBJECTS GIVEN BELOW HAS THE SHAPE OF A CONE.
PLANE AND CURVED SURFACES
EACH SOLID OCCUPIES SPACE. THE PART OF THE SOLID WHICH WE USUALLY SEE AND TOUCH IS CALLED SURFACE OF THE SOLID.
A. LOOK AT THE SURFACES OF THE OBJECTS SHOWN BELOW :
SOME SOLIDS HAVE ONLY PLANE SURFACE(S) AND SOME HAVE ONLY CURVED SURFACE WHILE SOME HAVE BOTH PLANE AND CURVED SURFACES AS WELL.
THE ABOVE OBJECTS HAVE ONLY PLANE SURFACE.
B. LOOK AT THE SURFACES OF THE OBJECTS SHOWN BELOW :
THE ABOVE OBJECTS HAVE ONLY CURVED SURFACE.
C. LOOK AT THE SURFACES OF THE OBJECTS SHOWN BELOW :
THE ABOVE OBJECTS HAVE BOTH PLANE AS WELL AS CURVED SURFACES.
COMMON SOLIDS
CUBOID : A CUBOID HAS 6 PLANE SURFACES CALLED ITS FACES. THEY ALL ARE RECTANGLES. IT HAS 12 EDGES AND 8 CORNERS OR VERTICES.
THE OPPOSITE SURFACES OF A CUBOID ARE IDENTICAL.
CUBE : A CUBE ALSO HAS 6 PLANE SURFACES CALLED ITS FACES. THEY ALL ARE SQUARES. IT HAS 12 EDGES AND 8 VERTICES. ALL THE SURFACES OF A CUBE ARE IDENTICAL.
DISTINCTION BETWEEN A CUBE AND A CUBOID
IN THE CASE OF A CUBOID, THE OPPOSITE FACES ARE IDENTICAL AND THEY MAY NOT BE SQUARES WHEREAS IN THE CASE OF CUBE ALL THE FACES ARE IDENTICAL (THEY ARE SQUARES).
CYLINDER : A CYLINDER HAS TWO PLANE FACES, ITS TOP AND BASE. IT HAS ONE CURVED FACE. IT HAS TWO EDGES WHERE THE CURVED FACE MEETS ITS PLANE FACES. IT HAS NO VERTEX.
THE BASE AND TOP OF A CYLINDER ARE OF THE SAME SHAPE AND SIZE.
CONE : A CONE HAS ONLY ONE PLANE FACE (ITS BASE) AND ONLY ONE CURVED FACE. IT HAS ONE VERTEX. IT HAS ONE EDGE WHERE THE CURVED FACE MEETS THE PLANE FACE.
SPHERE : IT HAS ONLY ONE CURVED FACE. IT DOES NOT HAVE ANY VERTEX OR EDGE.
A. LOOK AT THE SURFACES OF THE OBJECTS SHOWN BELOW :
SOME SOLIDS HAVE ONLY PLANE SURFACE(S) AND SOME HAVE ONLY CURVED SURFACE WHILE SOME HAVE BOTH PLANE AND CURVED SURFACES AS WELL.
B. LOOK AT THE SURFACES OF THE OBJECTS SHOWN BELOW :
C. LOOK AT THE SURFACES OF THE OBJECTS SHOWN BELOW :
COMMON SOLIDS
CUBOID : A CUBOID HAS 6 PLANE SURFACES CALLED ITS FACES. THEY ALL ARE RECTANGLES. IT HAS 12 EDGES AND 8 CORNERS OR VERTICES.
THE OPPOSITE SURFACES OF A CUBOID ARE IDENTICAL.
IN THE CASE OF A CUBOID, THE OPPOSITE FACES ARE IDENTICAL AND THEY MAY NOT BE SQUARES WHEREAS IN THE CASE OF CUBE ALL THE FACES ARE IDENTICAL (THEY ARE SQUARES).
CYLINDER : A CYLINDER HAS TWO PLANE FACES, ITS TOP AND BASE. IT HAS ONE CURVED FACE. IT HAS TWO EDGES WHERE THE CURVED FACE MEETS ITS PLANE FACES. IT HAS NO VERTEX.
CONE : A CONE HAS ONLY ONE PLANE FACE (ITS BASE) AND ONLY ONE CURVED FACE. IT HAS ONE VERTEX. IT HAS ONE EDGE WHERE THE CURVED FACE MEETS THE PLANE FACE.
B. A CUBE HAS............EDGES.
C. A CUBE HAS............SQUARE FACES.
B. A CUBOID HAS............EDGES.
C. A CUBOID HAS............RECTANGULAR FACES.
B. A CYLINDER HAS............CURVED SURFACE.
B. A CONE HAS............CURVED SURFACE.
C. A CONE HAS............CORNER.
04 / MARCH / 2021
MATHEMATICS
MATHEMATICS
Now watch these videos to understand better:
Conversion of days into hours and hours into minutes:
1 day = 24 hours1 hour = 60 minutes1 week = 7 days1 month = 30 days1 year = 12 months
To convert days into hours :As we know, 1 day = 24 hours, so to convert days into hours, we simply multiply the number of days by 24.
To convert hours into minutes :1 hour = 60 minutes, so to convert hours into minutes, we simply multiply the number of hours by 60.
Assignment: Complete the following in your Mathematics-OCB.Mathematics book, Pg No. 200,201 Ex No. 14C, Do No .1 to 5.
1 hour = 60 minutes
1 week = 7 days
1 month = 30 days
1 year = 12 months
To convert days into hours :
As we know, 1 day = 24 hours, so to convert days into hours, we simply multiply the number of days by 24.
To convert hours into minutes :
1 hour = 60 minutes, so to convert hours into minutes, we simply multiply the number of hours by 60.
Assignment: Complete the following in your Mathematics-OCB.
Mathematics book, Pg No. 200,201 Ex No. 14C, Do No .1 to 5.
01 / MARCH / 2021
MATHEMATICS
MATHEMATICS
CHAPTER 14 MEASURE OF TIME
As we know that a day has 24 hours but we can show only 12 hours on the face of a clock. Due to this the day is generally divided into two halves. The first half is from 12 o'clock in the night (midnight) to 12 o'clock at noon. These hours (12 hours) are taken as morning hours. To show time from midnight to noon,we write a.m.
The time from 12 noon to 12 midnight is the second half. These hours (12 hours) are taken as afternoon or evening hours. To show time from 12 noon to 12 midnight we write p.m.
Example: We write 9 o'clock in the morning as 9 a.m. and 9 o'clock in the evening as 9 p.m.
A 24-hour clock is used in bus and railway timetables, airline schedules, etc. In a 24-hour clock, time runs from midnight to midnight. In a 24-hour clock system, a.m. or p.m. is not used. In this system, instead of using 12 numbers, we use numbers from 0 to 24 to represent the 24-hours of a day.
Now, it is clear from the above table that from midnight to 1 2 : 00 noon, time remains same on both the 1 2-hour clock and the 24-hour clock.
Now, we observe the following table to compare the 12-hour clock time with the 24-hour clock time.
Thus, from the above table, we see that :
The time in the 24-hour clock is represented in four digit numbers.
a. 12 midnight is denoted by 24 : 00 hours or 00 : 00 hours.
b. 12 noon is denoted by 12 : 00 hours.
For example : 09 : 10 hours ➔ 9 : 10 a.m. and 11 : 50 hours ➔ 11 : 50 a.m.
c. If the number formed by the first two digits from the left is 12 (other than 12 : 00), it shows 12 hours afternoon and so p.m. is to be used with it.
For example : 12 : 10 hours ➔ 12 : 10 p.m. and 12 : 58 hours ➔ 12 : 58 p.m.
d. If the numeral formed by the first two digits from the left is greater than 12, we subtract 12 from it to get the number of hours after the noon and so p.m. is used with this time.
For example: 14: 1 0 hours➔ 2 : 1 0 p.m. and 1 2:50 hours➔ 9 : 50 p.m.Assignment: Complete the following in your Mathematics-OCB.Mathematics book, Pg No. 198, Ex No. 14 B, Do No. 1 to 3.
As we know that a day has 24 hours but we can show only 12 hours on the face of a clock. Due to this the day is generally divided into two halves. The first half is from 12 o'clock in the night (midnight) to 12 o'clock at noon. These hours (12 hours) are taken as morning hours. To show time from midnight to noon,we write a.m.
The time from 12 noon to 12 midnight is the second half. These hours (12 hours) are taken as afternoon or evening hours. To show time from 12 noon to 12 midnight we write p.m.
Example: We write 9 o'clock in the morning as 9 a.m. and 9 o'clock in the evening as 9 p.m.
A 24-hour clock is used in bus and railway timetables, airline schedules, etc. In a 24-hour clock, time runs from midnight to midnight. In a 24-hour clock system, a.m. or p.m. is not used. In this system, instead of using 12 numbers, we use numbers from 0 to 24 to represent the 24-hours of a day.
Now, it is clear from the above table that from midnight to 1 2 : 00 noon, time remains same on both the 1 2-hour clock and the 24-hour clock.
Now, we observe the following table to compare the 12-hour clock time with the 24-hour clock time.
Thus, from the above table, we see that :
The time in the 24-hour clock is represented in four digit numbers.
a. 12 midnight is denoted by 24 : 00 hours or 00 : 00 hours.
b. 12 noon is denoted by 12 : 00 hours.
The time in the 24-hour clock is represented in four digit numbers.
a. 12 midnight is denoted by 24 : 00 hours or 00 : 00 hours.
b. 12 noon is denoted by 12 : 00 hours.
For example : 09 : 10 hours ➔ 9 : 10 a.m. and 11 : 50 hours ➔ 11 : 50 a.m.
c. If the number formed by the first two digits from the left is 12 (other than 12 : 00), it shows 12 hours afternoon and so p.m. is to be used with it.
c. If the number formed by the first two digits from the left is 12 (other than 12 : 00), it shows 12 hours afternoon and so p.m. is to be used with it.
For example : 12 : 10 hours ➔ 12 : 10 p.m. and 12 : 58 hours ➔ 12 : 58 p.m.
d. If the numeral formed by the first two digits from the left is greater than 12, we subtract 12 from it to get the number of hours after the noon and so p.m. is used with this time.
d. If the numeral formed by the first two digits from the left is greater than 12, we subtract 12 from it to get the number of hours after the noon and so p.m. is used with this time.
For example: 14: 1 0 hours➔ 2 : 1 0 p.m. and 1 2:50 hours➔ 9 : 50 p.m.
Assignment: Complete the following in your Mathematics-OCB.
Mathematics book, Pg No. 198, Ex No. 14 B, Do No. 1 to 3.
25 / FEBRUARY / 2021
MATHEMATICS
MATHEMATICS
CHAPTER 14 MEASURE OF TIMENow watch this video for better understanding: * A clock is used to measure time.
* The short hand is called the hour hand.
* The long hand is called the minute hand.
* The hour hand takes 12 hours to complete one round.
* The minute hand takes 1 hour to complete one round.
* An hour (h) and minute (min) are the standard units for the measurement of time.
* The hour hand shows the hours and the minute hand shows the minutes.
When the minute hand moves all the way round the clock, i.e., from 12 to 12, an hour passes :
In the clock shown the hour hand is between 5 and 6 and the minute hand is at 6. The shaded part shows that the long hand or minute hand has moved half way round. When the minute hand moves half (1/2) way round the face of clock half an hour has passed and we say that it is half past five.
Also,
Hour hand is between 4 and 5. Minute hand is at 6.Time is Half past 4 or 4 : 30
Assignment : Complete the following in your Mathematics-OCB.Mathematics book, Pg No.193 to 196, Ex No. 14A ,Do No. 1 ,2 in OCB and 3 to 6 in the text book.
* A clock is used to measure time.
* The short hand is called the hour hand.
* The long hand is called the minute hand.
* The hour hand takes 12 hours to complete one round.
* The short hand is called the hour hand.
* The long hand is called the minute hand.
* The hour hand takes 12 hours to complete one round.
* The minute hand takes 1 hour to complete one round.
* An hour (h) and minute (min) are the standard units for the measurement of time.
* The hour hand shows the hours and the minute hand shows the minutes.
When the minute hand moves all the way round the clock, i.e., from 12 to 12, an hour passes :
In the clock shown the hour hand is between 5 and 6 and the minute hand is at 6. The shaded part shows that the long hand or minute hand has moved half way round. When the minute hand moves half (1/2) way round the face of clock half an hour has passed and we say that it is half past five.
Also,
Time is Half past 4 or 4 : 30
11 / FEBRUARY / 2021
MATHEMATICS
MATHEMATICS
Chapter 12 Measurement of Weight
Chapter 12 Measurement of Weight
Word problems on subtraction:Now watch this video for better understanding: Assignment: Complete the following in your Mathematics-OCB.Mathematics book, Pg No. 178,179, Ex No.12C ,Do No. 29,31,33,35,37,39.
Word problems on subtraction:
Now watch this video for better understanding:
Assignment: Complete the following in your Mathematics-OCB.
Mathematics book, Pg No. 178,179, Ex No.12C ,Do No. 29,31,33,35,37,39.
08 / FEBRUARY / 2021
MATHEMATICS
MATHEMATICS
Chapter 12 Measurement of Weight
Chapter 12 Measurement of Weight
Subtraction: Kilograms and grams
Now watch this video for better understanding:Assignment: Complete the following in your Mathematics-OCB.Mathematics book, Pg No. 178,Ex No. 12C, Do No. 1 to 13, 22 to 28.Do No. 14 to 21 in the text book.
Subtraction: Kilograms and grams
Now watch this video for better understanding:
Assignment: Complete the following in your Mathematics-OCB.
Mathematics book, Pg No. 178,Ex No. 12C, Do No. 1 to 13, 22 to 28.
Do No. 14 to 21 in the text book.
04 / FEBRUARY / 2021
04 / FEBRUARY / 2021
MATHEMATICS
MATHEMATICS
Chapter 12 Measurement of WeightWord problems on addition:Now watch this video for your better understanding 
Assignment: Complete the following in your Mathematics-OCB.Mathematics book, Pg No. 174,175,Ex No. 12B, Do No. 27 to 36.
Chapter 12 Measurement of Weight
Word problems on addition:
Now watch this video for your better understanding
Assignment: Complete the following in your Mathematics-OCB.
Mathematics book, Pg No. 174,175,Ex No. 12B, Do No. 27 to 36.
01 / FEBRUARY / 2021
MATHEMATICS
MATHEMATICS
Chapter 12 Measurement of Weight
Chapter 12 Measurement of Weight
Now watch this video for your better understanding: Assignment: Complete the following in your Mathematics-OCB.Mathematics book, Pg No. 174, Ex No. 12 B, Do No. 1 to 14.Do No. 15 to 26 in the text book.
Now watch this video for your better understanding:
28 / JANUARY / 2021
MATHEMATICS
MATHEMATICS
Chapter 12 Measurement of WeightNow watch this video for your better understanding:To measure how heavy something is, or how light another is, we use measures of weight.
The unit of weight in metric system is gram. We measure small amounts in grams. In olden times, most of the countries including our country weighed things in pounds and ounces. Nowadays most of the people use grams and kilograms to weigh things.
We use kilograms to weigh heavy things and use grams to weigh lighter ones.
The following standard weights are used to measure weight of different objects:
CONVERSIONS
Assignment: Complete the following in your Mathematics-OCB.Mathematics book, Pg No. 170, Ex No. 12 A, Do No. 1 to 31.
Chapter 12 Measurement of Weight
Now watch this video for your better understanding:
To measure how heavy something is, or how light another is, we use measures of weight.
The unit of weight in metric system is gram. We measure small amounts in grams. In olden times, most of the countries including our country weighed things in pounds and ounces. Nowadays most of the people use grams and kilograms to weigh things.
We use kilograms to weigh heavy things and use grams to weigh lighter ones.
The following standard weights are used to measure weight of different objects:
CONVERSIONS
Assignment: Complete the following in your Mathematics-OCB.
Mathematics book, Pg No. 170, Ex No. 12 A, Do No. 1 to 31.
25 / JANUARY / 2021
MATHEMATICS
MATHEMATICS
Chapter 11 Measurement of Length
Chapter 11 Measurement of Length
Word problems
Assignment: Complete the following in your Mathematics-OCB.Mathematics book, Pg No. 166,167,Ex No. 11E, Do No. 22,24,26,28,30,32.
Word problems
Assignment: Complete the following in your Mathematics-OCB.
Mathematics book, Pg No. 166,167,Ex No. 11E, Do No. 22,24,26,28,30,32.
21 / JANUARY / 2021
MATHEMATICS
MATHEMATICS
Chapter 11 Measurement of Length
Chapter 11 Measurement of Length
Word problemsNow watch this video for your better understanding: 
Assignment: Complete the following in your Mathematics-OCB.Mathematics book, page No. 165,166, Ex No. 11E, Do No. 1 to 10.
Word problems
Now watch this video for your better understanding:
Assignment: Complete the following in your Mathematics-OCB.
Mathematics book, page No. 165,166, Ex No. 11E, Do No. 1 to 10.
18 / JANUARY / 2021
MATHEMATICS
MATHEMATICS
Chapter 11 Measurement of Length
Chapter 11 Measurement of Length
Now watch this video for your better understanding:
Assignment: Complete the following in your Mathematics-OCB.Mathematics book, page No. 163, Ex No. 11 D, Do No. 1 to 3 ,12 to 19 and 28 to 35.
Now watch this video for your better understanding:
Assignment: Complete the following in your Mathematics-OCB.
Mathematics book, page No. 163, Ex No. 11 D, Do No. 1 to 3 ,12 to 19 and 28 to 35.
11 / JANUARY / 2021
MATHEMATICS
MATHEMATICS
Chapter 11 Measurement of Length
Chapter 11 Measurement of Length
Assignment: Complete the following in your Mathematics-OCB.Mathematics book, Page No.160, Ex No. 11C,Do No. 1 to 9.
10 / DECEMBER / 2020
MATHEMATICS
MATHEMATICS
Chapter 11 Measurement of Length
Chapter 11 Measurement of Length
Addition and subtraction in metre and Centimetre.Now watch this video for better understanding:Example 1 : Add 25 m 77 cm and 47 m 35 cm.
Example 2 : Subtract 35 m 88 cm from 70 m 29 cm
ADDITION AND SUBTRACTION IN km AND m
Example 1 : Add 432 km 352 m and 352 km 276 m.
Solution :
Example 2 : Subtract 25 km 259 m from 48 km 408 m.
Solution :
Assignment: Complete the following in your Mathematics-OCB.Mathematics book Pg No. 158, Ex No. 11B, Do No. 1 to 11.
Addition and subtraction in metre and Centimetre.
Now watch this video for better understanding:
Example 1 : Add 25 m 77 cm and 47 m 35 cm.
Example 2 : Subtract 35 m 88 cm from 70 m 29 cm
ADDITION AND SUBTRACTION IN km AND m
Example 1 : Add 432 km 352 m and 352 km 276 m.
Solution :
Example 2 : Subtract 25 km 259 m from 48 km 408 m.
Solution :
Example 2 : Subtract 35 m 88 cm from 70 m 29 cm
ADDITION AND SUBTRACTION IN km AND m
Example 1 : Add 432 km 352 m and 352 km 276 m.
Solution :
Example 2 : Subtract 25 km 259 m from 48 km 408 m.
Solution :
Assignment: Complete the following in your Mathematics-OCB.
Mathematics book Pg No. 158, Ex No. 11B, Do No. 1 to 11.
07 / DECEMBER / 2020
MATHEMATICS
MATHEMATICS
Chapter 11 Measurement of LengthKilometer, Metre and Centimetre.Now watch this video for better understanding: In the olden days, parts of body were used to measure lengths. Below are some of the units which were used.
As these units varied from individual to individual, a need was felt for having standard units of length and so Metre was invented.
Metre is the standard unit of length.
In many parts of the world, the units named below are used. These are also used in our country.
It is clear from the above figure, 12 inches make 1 foot. 3 feet (plural of foot) make 1 yard.
Length is measured in metres in almost all the countries. Longer distances are measured in kilometres and smaller lengths in centimetres.
To measure length there are different kinds of metre scales available in the market, like metre rod, measuring tape and a ruler.
The cloth merchant measures the cloth with an iron rod called metre rod.
Metre rod is divided into 100 equal parts. The length of each part is called centimetre.
A 15 cm or 30 cm ruler is used to measure lengths in centimetres. To measure the length of an object, say, pencil, line up one end of pencil at 0 mark of the ruler. If the other end touches the 8 cm mark of the ruler, then it is 8 cm long.
Bigger unit of length
To measure longer distances, say, distance between two cities or distance between two countries etc., we use a bigger unit of length called kilometre. The short form of kilometre is ‘km.’
CONVERSION OF UNITS OF LENGTH
Assignment: Complete the following in your Mathematics-OCB.Mathematics book, Page No. 156, Ex No. 11A,Do No. 1 to 8.
Chapter 11 Measurement of Length
Kilometer, Metre and Centimetre.
Now watch this video for better understanding:
In the olden days, parts of body were used to measure lengths. Below are some of the units which were used.
As these units varied from individual to individual, a need was felt for having standard units of length and so Metre was invented.
Metre is the standard unit of length.
In many parts of the world, the units named below are used. These are also used in our country.
In many parts of the world, the units named below are used. These are also used in our country.
It is clear from the above figure, 12 inches make 1 foot. 3 feet (plural of foot) make 1 yard.
Length is measured in metres in almost all the countries. Longer distances are measured in kilometres and smaller lengths in centimetres.
Length is measured in metres in almost all the countries. Longer distances are measured in kilometres and smaller lengths in centimetres.
To measure length there are different kinds of metre scales available in the market, like metre rod, measuring tape and a ruler.
The cloth merchant measures the cloth with an iron rod called metre rod.
Metre rod is divided into 100 equal parts. The length of each part is called centimetre.
A 15 cm or 30 cm ruler is used to measure lengths in centimetres. To measure the length of an object, say, pencil, line up one end of pencil at 0 mark of the ruler. If the other end touches the 8 cm mark of the ruler, then it is 8 cm long.
Bigger unit of length
To measure longer distances, say, distance between two cities or distance between two countries etc., we use a bigger unit of length called kilometre. The short form of kilometre is ‘km.’
To measure longer distances, say, distance between two cities or distance between two countries etc., we use a bigger unit of length called kilometre. The short form of kilometre is ‘km.’
CONVERSION OF UNITS OF LENGTH
Assignment: Complete the following in your Mathematics-OCB.
Mathematics book, Page No. 156, Ex No. 11A,Do No. 1 to 8.
26 / NOVEMBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER 10 MONEY
Multiplication of money by a whole number.CONVERSIONS
MONEY-ADDITION AND SUBTRACTION
PROBLEMS ON ADDITION AND SUBTRACTION OF MONEY
MONEY : MULTIPLICATION
A. We multiply the same as we do for the ordinary numbers. However, in the product, we put the dot just before the last 2 digits to express the product in rupees.
PROBLEMS ON MONEY : MULTIPLICATION
Now watch this video for your better understanding:Assignment: Do the following in your Mathematics-OCB.Mathematics book, page No. 152, Ex No. 10 E, Do No. 9 to 16.
Multiplication of money by a whole number.
CONVERSIONS
MONEY-ADDITION AND SUBTRACTION
PROBLEMS ON ADDITION AND SUBTRACTION OF MONEY
MONEY : MULTIPLICATION
A. We multiply the same as we do for the ordinary numbers. However, in the product, we put the dot just before the last 2 digits to express the product in rupees.
A. We multiply the same as we do for the ordinary numbers. However, in the product, we put the dot just before the last 2 digits to express the product in rupees.
PROBLEMS ON MONEY : MULTIPLICATION
Now watch this video for your better understanding:
Assignment: Do the following in your Mathematics-OCB.
Mathematics book, page No. 152, Ex No. 10 E, Do No. 9 to 16.
23 / NOVEMBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER 10 MONEY
Assignment: Do the following in your Mathematics-OCB.Mathematics book, Pg No.151, Ex No. 10 D ,Do No. 13 to 23.Four of them have been done for you.
13) Sunita has Rs 256.80 and her sister Kavita has Rs 324.40. How much more money does Kavita have than Sunita?Amount of money Kavita has = Rs 324.40Amount of money Sunita has = Rs 256.80. Rs 324. 40 - Rs 256. 80 Rs 67. 60Kavita has more Rs 67.60 than Sunita.
16) Saurabh purchased a bread for Rs 23.85, butter for Rs 69.75, eggs for Rs 23.39 and a cake for Rs 78.69. He gave the shopkeeper a 500 rupee note . How much money did he get back?
Cost of a bread = Rs 23.85Cost of butter = Rs + 69. 75Cost of eggs = Rs + 23. 39Cost of a cake = Rs + 78. 69 Total cost. = Rs 195. 68 Money given to the shopkeeper= Rs 500.Total cost = Rs 195.68 Rs 500.00- Rs 195. 68 Rs 304. 32 Money returned by the shopkeeper is Rs 304. 42.
19) Subtract the difference of Rs 289.30 and Rs 175.85 from Rs 500.50. Rs 289. 30- Rs 175. 85 Rs 113. 45 Rs 500. 50 - Rs 113. 45 Rs 387. 05
22) Satish bought a chair for Rs 100.40, a table for Rs 320.60, and a bench for Rs 205.60 . He gave one thousand rupee note to the shopkeeper. How much money did the shopkeeper return to him?Amount spent on a chair = Rs 100. 40Amount spent on a table = Rs + 320. 60Amount spent on a bench =Rs+ 205. 60 Total amount spent = Rs 626. 60 Money given to the shopkeeper= Rs 1000Total amount spent = Rs 626. 60 Rs 1000. 00-Rs 626. 60 Rs 373. 40 Amount returned by the shopkeeper to him is Rs 373.40.
Assignment: Do the following in your Mathematics-OCB.
Mathematics book, Pg No.151, Ex No. 10 D ,Do No. 13 to 23.
Four of them have been done for you.
13) Sunita has Rs 256.80 and her sister Kavita has Rs 324.40. How much more money does Kavita have than Sunita?
Amount of money Kavita has
= Rs 324.40
Amount of money Sunita has = Rs 256.80.
Rs 324. 40
- Rs 256. 80
Rs 67. 60
Kavita has more Rs 67.60 than Sunita.
16) Saurabh purchased a bread for Rs 23.85, butter for Rs 69.75, eggs for Rs 23.39 and a cake for Rs 78.69. He gave the shopkeeper a 500 rupee note . How much money did he get back?
Cost of a bread = Rs 23.85
Cost of butter = Rs + 69. 75
Cost of eggs = Rs + 23. 39
Cost of a cake = Rs + 78. 69
Total cost. = Rs 195. 68
Money given to the shopkeeper
= Rs 500.
Total cost = Rs 195.68
Rs 500.00
- Rs 195. 68
Rs 304. 32
Money returned by the shopkeeper is Rs 304. 42.
19) Subtract the difference of Rs 289.30 and Rs 175.85 from Rs 500.50.
Rs 289. 30
- Rs 175. 85
Rs 113. 45
Rs 500. 50
- Rs 113. 45
Rs 387. 05
22) Satish bought a chair for Rs 100.40, a table for Rs 320.60, and a bench for Rs 205.60 . He gave one thousand rupee note to the shopkeeper. How much money did the shopkeeper return to him?
Amount spent on a chair = Rs 100. 40
Amount spent on a table = Rs + 320. 60
Amount spent on a bench =Rs+ 205. 60
Total amount spent = Rs 626. 60
Money given to the shopkeeper
= Rs 1000
Total amount spent = Rs 626. 60
Rs 1000. 00
-Rs 626. 60
Rs 373. 40
Amount returned by the shopkeeper to him is Rs 373.40.
12 / NOVEMBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER 10 MONEY
Word problems on addition and subtraction :PROBLEMS ON ADDITION AND SUBTRACTION OF MONEY
Now watch this videos for better understanding:Assignment: Do the following in your Mathematics-OCBMathematics book, Pg No. 150, Ex No. 10 D, Do No. 1 to 12.
Word problems on addition and subtraction :
PROBLEMS ON ADDITION AND SUBTRACTION OF MONEY
Now watch this videos for better understanding:
Assignment: Do the following in your Mathematics-OCB
Mathematics book, Pg No. 150, Ex No. 10 D, Do No. 1 to 12.
09 / NOVEMBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER 10 MONEY
Subtraction of money
Now watch this video for better understanding:Assignment: Do the following in your Mathematics-OCBMathematics book, Pg No. 147,148, Ex No. 10 C, Do No. 1 to 11 and 20 to 31.
Subtraction of money
Now watch this video for better understanding:
Assignment: Do the following in your Mathematics-OCB
Mathematics book, Pg No. 147,148, Ex No. 10 C, Do No. 1 to 11 and 20 to 31.
05 / NOVEMBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER 10 MONEY
Converting amounts into various denominations.
Now watch this video for better understanding:MONEY-ADDITION AND SUBTRACTION
Assignment: Do the following in your Mathematics-OCBMathematics book, Pg No. 144, Ex No.10A, Do No. 6 to 10 and Pg No. 146 ,Ex No. 10 B, Do No.1 to 7 and 16 to 21.
Converting amounts into various denominations.
Now watch this video for better understanding:
MONEY-ADDITION AND SUBTRACTION
Assignment: Do the following in your Mathematics-OCBMathematics book, Pg No. 144, Ex No.10A, Do No. 6 to 10 and Pg No. 146 ,Ex No. 10 B, Do No.1 to 7 and 16 to 21.
02 / NOVEMBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER 10 MONEYNow watch this video for better understanding:Indian Currency
India money is in the form of coins and notes.Besides these coins ,we have currency notes in the denomination of one rupee,two rupees, five, ten, twenty, fifty hundred, two hundred, five hundred, and two thousand rupees.Symbols for Indian CurrencyThe symbol used for paise is 'p'.The singular of paise is paisa.The symbol used for rupees is Rs.The symbols for rupee and rupees are written before the number.Now watch this video for better understanding:Conversion of rupees into paisa:
Conversion of paisa into rupees:
Assignment: Do the following in your Mathematics-OCBMathematics book, Pg No. 143, Ex No. 10A ,Do No. 3 to 5.
India money is in the form of coins and notes.Besides these coins ,we have currency notes in the denomination of one rupee,two rupees, five, ten, twenty, fifty hundred, two hundred, five hundred, and two thousand rupees.
29 / OCTOBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER- 2Revision
CHAPTER- 2
Revision
ORDER RELATIONNow watch this video for better understanding:Now watch the video for better understanding:A number having more digits is greater than having fewer digits.If two numbers contain the same number of digits, we can compare them with the help of the digits on the extreme left. If this digit is the same in both the numbers, we compare the digits occupying the next place to its right and so on.
Example 1): Which is greater 2436 or 876?
Solution:2436 is a 4 digit number 876 is a 3 digit numberTherefore,2436>876
Example 2):which is greater 6725 or 3897
Solution:6725 has 6 thousand 3897 has 3 thousandTherefore,6725> 3897
Ascending order (smaller number to the greater number)Descending order (greater number to the smaller number)
Successor and Predecessor number:Now watch the video for better understanding:The number that comes just after a particular number is called its successor. The successor of a number is 1 more than the number.
The number that comes just before a particular number is called its predecessor. The predecessor of a number is 1 less than the number.
Skip countingIf starting with a given number we write some numbers with a fixed gap between two successive numbers, then such counting is called skip counting.
Skip counting by twos means that there is a gap of 2 in every successive number.
Skip counting by fives means that there is a gap of 5 in every successive number.
Skip counting by tens means that there is a gap of 10 in every successive number.
Skip counting by hundreds means that there is a gap of 100 in every successive number.Assignment: Do the following in your Mathematics-OCBMathematics book, Pg No.25 and 26, Do No. 4 to 10.
If two numbers contain the same number of digits, we can compare them with the help of the digits on the extreme left. If this digit is the same in both the numbers, we compare the digits occupying the next place to its right and so on.
Example 1): Which is greater 2436 or 876?
Solution:2436 is a 4 digit number
876 is a 3 digit number
Therefore,2436>876
Example 2):which is greater 6725 or 3897
Solution:6725 has 6 thousand
3897 has 3 thousand
Therefore,6725> 3897
Ascending order (smaller number to the greater number)
Descending order (greater number to the smaller number)
Successor and Predecessor number:
Now watch the video for better understanding:
The number that comes just after a particular number is called its successor. The successor of a number is 1 more than the number.
The number that comes just before a particular number is called its predecessor. The predecessor of a number is 1 less than the number.
Skip counting
If starting with a given number we write some numbers with a fixed gap between two successive numbers, then such counting is called skip counting.
Skip counting by twos means that there is a gap of 2 in every successive number.
Skip counting by fives means that there is a gap of 5 in every successive number.
Skip counting by tens means that there is a gap of 10 in every successive number.
Skip counting by hundreds means that there is a gap of 100 in every successive number.
Assignment: Do the following in your Mathematics-OCB
Mathematics book, Pg No.25 and 26, Do No. 4 to 10.
19 / OCTOBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER- 2RevisionPlace Value of 4-digit Numbers
CHAPTER- 2
Revision
Place Value of 4-digit Numbers
The place value of a digit in a 4-digit number depends upon the position it occupies.For example, the place value for the 3-digit number 1489 will be, (Look at the picture below):
From the place value chart, we have:The place value of 9 = 9 ones = 9The place value of 8 = 8 tens = 80The place value of 4 = 4 hundreds = 400The place value of 1 = 1 thousand = 1000
4-digit Number on an abacusWhat is an abacus?
THESE ARE PICTURES OF TWO DIFFERENT TYPES OF ABACUS they however, do the same thing. One is vertical while the other is horizontal.
Now watch the video for better understanding:Assignment:Do No. 2 to 10 on page No. 20 in the text book.
The place value of a digit in a 4-digit number depends upon the position it occupies.
For example, the place value for the 3-digit number 1489 will be, (Look at the picture below):
From the place value chart, we have:
The place value of 9 = 9 ones = 9
The place value of 8 = 8 tens = 80
The place value of 4 = 4 hundreds = 400
The place value of 1 = 1 thousand = 1000
4-digit Number on an abacus
What is an abacus?
THESE ARE PICTURES OF TWO DIFFERENT TYPES OF ABACUS they however, do the same thing. One is vertical while the other is horizontal.
Now watch the video for better understanding:
15 / OCTOBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER- 2RevisionNumbers upto 1000 and beyond 1000.
Explanation:Topic:1) Numbers upto 1000 and beyond 10,000.
We know that10 ones make 1 ten10 tens make 1 hundred10 hundreds make 1 thousand
We write one thousand as 10001000 can be obtained by adding 1 to 999 999+1= 1000We observe that 999 is the greatest three digit number.1000 is the smallest four digit number.
Numbers beyond 10001000+1= 1001By adding 1 we are able to get numbers beyond.Therefore 9999+1= 10,0009999 is the greatest four digit number.10,000 is the smallest five digit number.
Now watch the video for better understanding:
Assignment: Do No. 2 to 6, Pg No. 14 to 16 in the text book.
CHAPTER- 2
Revision
Numbers upto 1000 and beyond 1000.
Explanation:
Topic:1) Numbers upto 1000 and beyond 10,000.
We know that
10 ones make 1 ten
10 tens make 1 hundred
10 hundreds make 1 thousand
We write one thousand as 1000
1000 can be obtained by adding 1 to 999
999+1= 1000
We observe that 999 is the greatest three digit number.
1000 is the smallest four digit number.
Numbers beyond 1000
1000+1= 1001
By adding 1 we are able to get numbers beyond.
Therefore 9999+1= 10,000
9999 is the greatest four digit number.
10,000 is the smallest five digit number.
Now watch the video for better understanding:
Assignment:
Do No. 2 to 6, Pg No. 14 to 16 in the text book.
12 / OCTOBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER 9 ROMAN NUMERALS
CHAPTER 9 ROMAN NUMERALS
Now watch the video for better understanding:
1. Express the following in Roman Numeralsa) 7 Solution: 7 = 5 + 2 = V + II = VII
b) 24Solution:24 = 20 + 4 = XX + IV = XXIV
2. Express the following in Hindu- Arabic numerals:a) XVSolution:XV = 10 + 5 = 15.
b) XXVIIISolution:XXVIII = 20 + 8 = 28.
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Page No. 137, 138 Do No. 1 to 4.
Now watch the video for better understanding:
1. Express the following in Roman Numerals
a) 7
Solution:
7 = 5 + 2 = V + II = VII
b) 24
Solution:
24 = 20 + 4 = XX + IV = XXIV
2. Express the following in Hindu- Arabic numerals:
a) XV
Solution:
XV = 10 + 5 = 15.
b) XXVIII
Solution:
XXVIII = 20 + 8 = 28.
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Page No. 137, 138 Do No. 1 to 4.
08 / OCTOBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER 9 ROMAN NUMERALSNow watch the video for better understanding:
In the previous class we have studied numerals 0,1,2,3,4,5,6,7,8 and 9. These numerals were first used by Hindus and later by Arabians. Thus, these numerals are called Hindu- Arabic numerals.The numeral used in ancient Rome are called Roman Numerals. The Roman numerals are formed by only 7 symbols: I,V,X,L,C,D and M.
Assignment: Complete all exercises in your Mathematics-OCBWrite down the Roman Numerals from 1 to 40 .
CHAPTER 9 ROMAN NUMERALS
Now watch the video for better understanding:
In the previous class we have studied numerals 0,1,2,3,4,5,6,7,8 and 9. These numerals were first used by Hindus and later by Arabians. Thus, these numerals are called Hindu- Arabic numerals.
The numeral used in ancient Rome are called Roman Numerals. The Roman numerals are formed by only 7 symbols: I,V,X,L,C,D and M.
24 / SEPTEMBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER 1( Revision )
CHAPTER 1
( Revision )
Addition on word problemsNow watch this video for better understanding:Assignment: Complete all exercises in your Mathematics-OCBMathematics book, Pg No.3, Do No.28 to 33.Two of them have been done for you.
28) Number of pages in the first book = 3 1 2Number of pages in the second book = + 4 6 9Number of pages in the third book = 1 3 2 9 1 3Hence, she read 913 pages.
32) Numbers of eggs sold on Monday = 2 5 8 Number of eggs sold on Tuesday = + 3 6 9 6 2 7Hence, he sold 627 eggs.
Addition on word problems
Now watch this video for better understanding:
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No.3, Do No.28 to 33.
Two of them have been done for you.
28) Number of pages in the first book = 3 1 2
Number of pages in the second book = + 4 6 9
Number of pages in the third book = 1 3 2
9 1 3
Hence, she read 913 pages.
32) Numbers of eggs sold on Monday = 2 5 8
Number of eggs sold on Tuesday = + 3 6 9
6 2 7
Hence, he sold 627 eggs.
21 / SEPTEMBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER 1( Revision )
CHAPTER 1
( Revision )
Now watch these videos for better understanding:1. Arrange in columns and add:a) 489 + 65b) 279 + 156 + 87c) 700 + 77 + 7d) 256 + 379 + 262
2. Arrange in columns and find the difference:a) 525 - 386b) 800 - 709c) 721 - 649d) 800 - 697
Assignment: Complete all exercises in your Mathematics text book .
Mathematics book Pg No.2 and 3 Do No. 23, 25 and 26.
Now watch these videos for better understanding:
1. Arrange in columns and add:
a) 489 + 65
b) 279 + 156 + 87
c) 700 + 77 + 7
d) 256 + 379 + 262
2. Arrange in columns and find the difference:
a) 525 - 386
b) 800 - 709
c) 721 - 649
d) 800 - 697
14 / SEPTEMBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER 1( Revision )Now watch these videos for better understanding:
1. Write the following numbers in words:a) 45 b) 816 c) 999 d) 718 e) 587.2. Write the following numbers in figures:a) Seventy four b) Ninety four c) Two hundred seventy eight d) Nine hundred seventy e) Three hundred and seventy five.3. Write the following in short form:a) 6 hundreds + 3 tens + 2 onesb) 4 hundreds + 6 tens + 9 onesc) 3 hundreds + 7 tens + 4 onesd) 3 hundreds + 5 tens + 0 onee) 4 hundreds + 0 ten + 7 ones4. Write the following in the expanded form:a) 369 = _________ + ________ + __________.b) 719 = _________ + ________ + __________.c) 850 = _________ + ________ + __________.d) 607 = _________ + ________ + __________.e) 993 = _________ + ________ + __________.
Assignment: Complete all exercises in your Mathematics-OCBMathematics book Pg No.106, 107 Do No.11 to 18.
CHAPTER 1
( Revision )
Now watch these videos for better understanding:
1. Write the following numbers in words:
a) 45 b) 816 c) 999 d) 718 e) 587.
2. Write the following numbers in figures:
a) Seventy four b) Ninety four c) Two hundred seventy eight d) Nine hundred seventy e) Three hundred and seventy five.
3. Write the following in short form:
a) 6 hundreds + 3 tens + 2 ones
b) 4 hundreds + 6 tens + 9 ones
c) 3 hundreds + 7 tens + 4 ones
d) 3 hundreds + 5 tens + 0 one
e) 4 hundreds + 0 ten + 7 ones
4. Write the following in the expanded form:
a) 369 = _________ + ________ + __________.
b) 719 = _________ + ________ + __________.
c) 850 = _________ + ________ + __________.
d) 607 = _________ + ________ + __________.
e) 993 = _________ + ________ + __________.
Mathematics book Pg No.106, 107 Do No.11 to 18.
10 / SEPTEMBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER- 8 FRACTIONS
CHAPTER- 8 FRACTIONS
NUMERATOR AND DENOMINATORNow watch this video to help you understand better. 
A fraction is expressed by writing two numbers, one over the other and separated by a horizontal line '______ ' . The number above the line tells us the number of parts which are taken. This number is called the Numerator of fraction. The number below the line tells us the number of equal parts into which the whole is divided. This number is called the Denominator of the fraction.
Assignment: Complete all exercises in your Mathematics-OCBMathematics book, Pg No.105,106 Do No. 6 to 10.
NUMERATOR AND DENOMINATOR
Now watch this video to help you understand better.
07 / SEPTEMBER / 2020
MATHEMATICS
MATHEMATICS
CHAPTER- 8 FRACTIONS
A fraction is the part of a whole object. lt has two parts - a Numerator and a DenominatorOne- Half: When a whole number is divided into two equal parts ,each one of the two parts is called one- half of the whole.The symbol used for expressing one- half is 1/2, which is read as ' one by two' or 'one over two'.
Now watch this video to help you understand better:
Assignment: Complete all exercises in your Mathematics-OCBMathematics book, Pg No. 104, 105 Do No. 1 to 5.
CHAPTER- 8 FRACTIONS
A fraction is the part of a whole object. lt has two parts - a Numerator and a Denominator
One- Half: When a whole number is divided into two equal parts ,each one of the two parts is called one- half of the whole.The symbol used for expressing one- half is 1/2, which is read as ' one by two' or 'one over two'.
Now watch this video to help you understand better:
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 104, 105 Do No. 1 to 5.
14 / AUG / 2020
MATHEMATICS
MATHEMATICS
RevisionChapter 1Assignment: Complete all exercises in your Mathematics-OCBA. Write the fraction of the following in the box:
B. Give the name of the geometrical figure to which of the following figures look like:
Revise Chapters 1 and 2 for Formative Assessment on 18/08/2020.
Revision
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCB
A. Write the fraction of the following in the box:
B. Give the name of the geometrical figure to which of the following figures look like:
Revise Chapters 1 and 2 for Formative Assessment on 18/08/2020.
13 / AUG / 2020
MATHEMATICS
MATHEMATICS
RevisionChapter 1Assignment: Complete all exercises in your Mathematics-OCB
Revision
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCB
Solve these:1) Ram has 35 pencils. There are 5 pencils in each box . How many boxes of pencils does he have?2) There are 6 school days in one school week. How many weeks of school are in 24 school days?3) The owner of the petrol pump purchased 985 litres of petrol. He sold 599 litres of petrol. How much petrol was left with him?4) A milk dairy sells 125 litres of milk everyday. How much milk will it sell in 4 days?
Solve these:
1) Ram has 35 pencils. There are 5 pencils in each box . How many boxes of pencils does he have?
2) There are 6 school days in one school week. How many weeks of school are in 24 school days?
3) The owner of the petrol pump purchased 985 litres of petrol. He sold 599 litres of petrol. How much petrol was left with him?
4) A milk dairy sells 125 litres of milk everyday. How much milk will it sell in 4 days?
11 / AUG / 2020
MATHEMATICS
MATHEMATICS
RevisionChapter 1Assignment: Complete all exercises in your Mathematics-OCB
Revision
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCB
Divide and find the quotient:a) 42 ÷ 6b) 64 ÷ 8c) 36 ÷ 9d) 86 ÷ 7e) 660 ÷ 6 f) 695 ÷ 50g) 246 ÷ 5h) 861 ÷ 86
10 / AUG / 2020
MATHEMATICS
MATHEMATICS
RevisionChapter 1Assignment: Complete all exercises in your Mathematics-OCBMathematics book, Pg No.4 and 5, Do No. 41 to 44 and 59 to 61.Two of them have been done for you.
41) Number of balloons in 1 packet = 15Number of balloons in 8 packets = 15 x 8 = 120 balloons.Hence, 8 packets contain 120 balloons.
59) Cost of 1 eraser = Rs 9Cost of 1 notebook = Rs 2 0 Cost of 1 pencil box = + Rs 7 0 Rs 9 9 Amount paid = Rs 100Amount returned = Rs 100 - Rs 99 = Re1.
Revision
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCB
07 / AUG / 2020
MATHEMATICS
MATHEMATICS
SELF ASSESSMENT TESTGeneral Instructions:1. Read the questions carefully.2. Each answer is of one mark.3. Click on the submit button after completing the test.4. The test must be completed in 30 minutes.5. The test will start at 1:00 pm and ends at 1:30 pm.Note: It is mandatory to write your name and four digit registration number.
The Link to attempt the SAT will be sent to you on WhatsApp before 1PM today i.e07/08/2020. You only have one attempt and must complete the Test in 30 minutes.
SELF ASSESSMENT TEST
The Link to attempt the SAT will be sent to you on WhatsApp before 1PM today i.e
06 / AUG / 2020
MATHEMATICS
MATHEMATICS
REVISION
REVISION
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCBMathematics book, Pg No. 4, Do No. 45 to 52.
Assignment: Complete all exercises in your Mathematics-OCB
05 / AUG / 2020
MATHEMATICS
MATHEMATICS
REVISION
REVISION
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCBMathematics book, Pg No. 3. Do No. 34 to 38.One of them have been done for you.
36) Total number of mangoes = 9 3 5Number of mangoes sold = - 3 8 6 Number of mangoes left = 5 4 9
Hence, 549 mangoes are left.
Assignment: Complete all exercises in your Mathematics-OCB
04 / AUG / 2020
MATHEMATICS
MATHEMATICS
REVISION
REVISION
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCBMathematics book, Pg No.3, Do No.28 to 33.Two of them have been done for you.
28) Number of pages in the first book = 3 1 2Number of pages in the second book = + 4 6 9Number of pages in the third book = 1 3 2 9 1 3 Hence, she reads 913 pages.
32) Numbers of eggs sold on Monday = 2 5 8 Number of eggs sold on Tuesday = + 3 6 9 6 2 7Hence, he sold 627 eggs.
Revise chapter 1 pages (1 to 3) for Self Assessment Test (SAT) on 07/08/2020. Timing: 1:00 pm to 1:30 pm.
Assignment: Complete all exercises in your Mathematics-OCB
31 / JULY / 2020
MATHEMATICS
MATHEMATICS
REVISION
REVISION
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCBMathematics book, page No.4, Do No. 40 (a to h)Two of them have been done for you.a) 3 4 0 g) 7 9 6 X 2 X 5 6 8 0 3 9 8 0
Assignment: Complete all exercises in your Mathematics-OCB
a) 3 4 0 g) 7 9 6
X 2 X 5
6 8 0 3 9 8 0
30 / JULY / 2020
MATHEMATICS
MATHEMATICS
REVISION
REVISION
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCB1. Simplify :a) 425 + 312 - 209b) 229 + 506 - 413c) 539 - 387 + 297d) 816 - 609 + 116e) 700 - 429 + 246f) 329 - 196 + 457 - 362
Assignment: Complete all exercises in your Mathematics-OCB
29 / JULY / 2020
MATHEMATICS
MATHEMATICS
REVISION
REVISION
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCB1. Arrange in columns and add:a) 489 + 65b) 279 + 156 + 87c) 700 + 77 + 7d) 256 + 379 + 262
2. Arrange in columns and find the difference:a) 525 - 386b) 800 - 709c) 721 - 649d) 800 - 697
Assignment: Complete all exercises in your Mathematics-OCB
1. Arrange in columns and add:
a) 489 + 65
b) 279 + 156 + 87
c) 700 + 77 + 7
d) 256 + 379 + 262
2. Arrange in columns and find the difference:
a) 525 - 386
b) 800 - 709
c) 721 - 649
d) 800 - 697
28 / JULY / 2020
MATHEMATICS
MATHEMATICS
REVISION
REVISION
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCB1. Add:a) 5 0 7 b) 2 3 4 c) 2 7 6 + 2 8 3 + 6 7 9 3 9 5 + 1 0 7
2. Subtract:a) 7 8 b) 8 3 2 c) 6 0 5 - 5 9 - 5 4 6 - 4 1 9
Assignment: Complete all exercises in your Mathematics-OCB
27 / JULY / 2020
MATHEMATICS
MATHEMATICS
REVISION
REVISION
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCB1.Use <, > or = in the blank to make the following sentences correct:a) 725 _____ 737.b) 605 _____ 595.c) 200 _____ 210.d) 410 _____ 401.e) 980 _____ 890. f) 760 _____ 760.
2. Counting by twenties write numerals from 651 to 756.
Assignment: Complete all exercises in your Mathematics-OCB
1.Use <, > or = in the blank to make the following sentences correct:
a) 725 _____ 737.
b) 605 _____ 595.
c) 200 _____ 210.
d) 410 _____ 401.
e) 980 _____ 890.
f) 760 _____ 760.
2. Counting by twenties write numerals from 651 to 756.
2. Counting by twenties write numerals from 651 to 756.
24 / JULY / 2020
MATHEMATICS
MATHEMATICS
REVISION
REVISION
Chapter 1
Assignment: Complete all exercise in your Mathematics-OCB(One has been done for you).1. Answer the following questions:a) Write the greatest number of two digitsAns ) 99b) Write the smallest number of two digits.c) Write the greatest number of three digits.d) Write the smallest number of three digits.e) Which is greater 672 or 663? f) Which is smaller 965 or 956?g) Write the numbers between 656 and 663.h) How many 1 digit numbers are there?i) How many 2 digit numbers are there?j) How many 3 digit numbers are there?
Assignment: Complete all exercise in your Mathematics-OCB
(One has been done for you).
1. Answer the following questions:
a) Write the greatest number of two digits
Ans ) 99
b) Write the smallest number of two digits.
c) Write the greatest number of three digits.
d) Write the smallest number of three digits.
e) Which is greater 672 or 663?
f) Which is smaller 965 or 956?
g) Write the numbers between 656 and 663.
h) How many 1 digit numbers are there?
i) How many 2 digit numbers are there?
j) How many 3 digit numbers are there?
23 / JULY / 2020
MATHEMATICS
MATHEMATICS
REVISION
REVISION
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCB(One of each exercise has been done for you).1. Write the following in short form:a) 6 hundreds + 3 tens + 2 ones = 632b) 4 hundreds + 6 tens + 5 ones =c) 3 hundreds + 7 tens + 4 ones =d) 3 hundreds + 5 tens + 0 one =e) 4 hundreds + 0 ten + 7 ones =
2.Write each of the following in the expanded form:a) 369 = 300 + 60 + 9.b) 719 =c) 850 =d) 607 =e) 993 =
22 / JULY / 2020
MATHEMATICS
MATHEMATICS
REVISION
1. Write the following numbers in words:
2. Write the following numbers in figures:
REVISION
Chapter 1
Assignment: Complete all exercises in your Mathematics-OCB.
(One has been done for you in each exercise)
1. Write the following numbers in words:
a) 45 - Forty five
b) 816 -
c) 999-
d) 718-
e) 685-
2. Write the following numbers in figures:
a) Seventy four - 74
b) Eight hundred ten-
c) Two hundred seventy eight-
d) Nine hundred and seventy-
e) Two hundred and forty nine-
21 / JULY / 2020
MATHEMATICS
MATHEMATICS
Chapter 7 DIVISION
Assignment: Complete all exercises in your Mathematics-OCB Mathematics book, Pg No. 96, Ex No.7J, Do Nos. 30 to 33.
30) Number of plants in 9 rows = 936
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 96, Ex No.7J, Do Nos. 30 to 33.
Two of them have been done for you.
30) Number of plants in 9 rows = 936
Number of plants in 1 row = 936 ÷ 9 = 104.
9) 9 3 6 (104
9
0 3
0
3 6
3 6
0
32) Total number of papers = 1246
Number of teachers = 14
14) 1 2 4 6 (89
1 1 2
1 2 6
1 2 6
0
Hence, each teacher checks 89 papers.
20 / JULY / 2020
MATHEMATICS
MATHEMATICS
Chapter 7 DIVISION
Assignment: Complete all exercises in your Mathematics-OCB
26) Total number of chairs = 848
Hence, 53 chairs are kept in one room.28) Cost of 1 book = Rs 9Amount paid = Rs 5000
Hence, he bought 555 books and got back Rs 5.
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 96, Ex No. 7J, Do Nos. 25 to 29.
Two of them have been done for you.
26) Total number of chairs = 848
Number of rooms = 16
Number of chairs kept in 1 room = 848 ÷ 16 = 53.
16) 8 4 8 (53
8 0
4 8
4 8
0
Hence, 53 chairs are kept in one room.
Hence, 53 chairs are kept in one room.
28) Cost of 1 book = Rs 9
Amount paid = Rs 5000
Number of books bought = 5000 ÷ 9 = 555.
9) 5 0 0 0 (555
4 5
5 0
4 5
5 0
4 5
5
Hence, he bought 555 books and got back Rs 5.
Hence, he bought 555 books and got back Rs 5.
17 / JULY / 2020
MATHEMATICS
MATHEMATICS
Chapter 7 DIVISION
Assignment: Complete all exercises in your Mathematics-OCB Mathematics book, Pg No. 95,96 , Ex No. 7J, Do No. 19 to 24.
21) Product of two numbers = 8845One number = 5The other number = 8845 ÷ 5 = 1769.
5) 8 8 4 5 (1769
24) Total number of marbles = 988
19) 9 8 8 (52
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 95,96 , Ex No. 7J, Do No. 19 to 24.
21) Product of two numbers = 8845
One number = 5
The other number = 8845 ÷ 5 = 1769.
5) 8 8 4 5 (1769
5
3 8
3 5
3 4
3 0
4 5
4 5
0
Hence, the other number is 1769.
24) Total number of marbles = 988
Number of boys = 19.
Number of marbles that each boy gets
= 988 ÷ 19 = 52
19) 9 8 8 (52
9 5
3 8
3 8
0
Hence, each boy gets 52 marbles.
16 / JULY / 2020
MATHEMATICS
MATHEMATICS
Chapter 7 DIVISION
Assignment: Complete all exercises in your Mathematics-OCB
15) Total number of students = 852
6) 8 5 2 (142 6
17) Amount to be divided = Rs 747
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 95, Ex No. 7J, Do No. 13 to 18.
Two of them have been done for you.
15) Total number of students = 852
Number of students on 1 bench = 6
Number of benches needed for 852 students
= 852 ÷ 6 = 142.
6) 8 5 2 (142
6
2 5
2 4
1 2
1 2
0
Hence, 142 benches are needed for 852 students.
17) Amount to be divided = Rs 747
Number of girls = 3
Amount that each girl will get = 747 ÷ 3 = 249
3) 7 4 7 (249
6
1 4
1 2
2 7
2 7
0
Hence, each girl will get Rs 249.
15 / JULY / 2020
MATHEMATICS
MATHEMATICS
Chapter 7 DIVISION
Assignment: Complete all exercises in your Mathematics-OCB
9) Total number of players to be divided = 72
12) Number of seats in 9 rows = 369.
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No.95, Ex No. 7J, Do No. 7 to 12.
Two of them have been done for you.
9) Total number of players to be divided = 72
Number of teams = 6
Number of players in 1 team = 72 ÷ 6 = 12.
6) 7 2 (12
6
1 2
1 2
0
Hence, there are 12 players in each team.
12) Number of seats in 9 rows = 369.
Number of seats in 1 row = 369 ÷ 9 = 41.
9) 3 6 9 (41
3 6
0 9
9
0
Hence, in each row there are 41 seats.
14 / JULY / 2020
MATHEMATICS
MATHEMATICS
Chapter 7 DIVISION Word problems on Division
Assignment: Complete all exercises in your Mathematics-OCB
1) Total number of dolls = 56
6) Distance travelled by car in 4 hours = 288 kms
Hence, the distance travelled by car in 1 hour is 72 Kms.
Word problems on Division
NOW WATCH THE VIDEO.
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 95, Ex No. 7J, Do No. 1 to 6.
Two of them have been done for you.
1) Total number of dolls = 56
Number of girls = 7.
Number of dolls that a girl will get = 56 ÷ 7 = 8.
7 ) 5 6 ( 8
5 6
0
Hence, each girl will get 8 dolls.
6) Distance travelled by car in 4 hours = 288 kms
Distance travelled by car in 1 hour = 288 ÷ 4 = 72 Kms
4 ) 2 8 8 ( 72
2 8
8
8
0
Hence, the distance travelled by car in 1 hour is 72 Kms.
Hence, the distance travelled by car in 1 hour is 72 Kms.
13 / JULY / 2020
MATHEMATICS
MATHEMATICS
Chapter 7 DIVISION Assignment: Complete all exercises in your Mathematics-OCB
11) 7983 ÷ 17
14) 5679 ÷ 19
19) 7666 ÷ 14
Chapter 7 DIVISION
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No.93, Ex No. 7I, Do No. 11 to 20.
Three of them have been done for you.
11) 7983 ÷ 17
17) 7 9 8 3 (469
6 8
1 1 8
1 0 2
1 6 3
1 5 3
1 0
Quotient = 469, Remainder = 10.
14) 5679 ÷ 19
19) 5 6 7 9 (298
3 8
1 8 7
1 7 1
1 6 9
1 5 2
1 7
Quotient = 298, Remainder = 17.
19) 7666 ÷ 14
14) 7 6 6 6 (547
7 0
6 6
5 6
1 0 6
9 8
8
Quotient = 547, Remainder = 8.
10 / JULY / 2020
MATHEMATICS
MATHEMATICS
Chapter 7 DIVISION Division by two digit numbersNOW WATCH THE VIDEO.
Assignment: Complete all exercises in your Mathematics-OCB
1) 286 ÷ 13
9) 3918 ÷ 16
Chapter 7 DIVISION
Division by two digit numbers
NOW WATCH THE VIDEO.
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 93, Ex No. 7I , Do No.1 to 10.
Two of them have been done for you.
1) 286 ÷ 13
13) 2 8 6 (22
2 6
2 6
2 6
0
Quotient = 22, Remainder = 0.
9) 3918 ÷ 16
16) 3 9 1 8 (244
3 2
7 1
6 4
7 8
6 4
1 4
Quotient = 244, Remainder = 14.
09 / JULY / 2020
MATHEMATICS Chapter 7 DIVISION Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No.91, Ex No. 7H,Do No.11 to 20.
14) 900÷ 10
19) 7009 ÷ 10
Quotient = 700, Remainder = 9.
MATHEMATICS
Chapter 7 DIVISION
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No.91, Ex No. 7H,Do No.11 to 20.
Two of them have been done for you.
14) 900÷ 10
10) 9 0 0 (90
9 0
0 0
0
0
Quotient = 90, Remainder = 0.
19) 7009 ÷ 10
10) 7 0 0 9 (700
7 0
0 0
0
0 9
0
9
Quotient = 700, Remainder = 9.
08 / JULY / 2020
MATHEMATICS
Chapter 7 DIVISION
Division by 10
NOW WATCH THE VIDEO.
Explanation:
Explanation:
a) Divide 63 by 10
Solution:
Solution:
Quotient = 6, Remainder = 3.
b) Divide 796 by 10
Solution:
When we divide a number by 10, the quotient is obtained by removing the digit at the units place from the number. Also the digit at the units place is the remainder.
Assignment: Complete all exercises in your Mathematics- OCB
Mathematics book, Pg No. 91, Ex No. 7H, Do No. 1 to 10.
Two of them have been done for you.
1) 65 ÷ 10
10) 6 5 (6
6 0
5
Quotient = 6, Remainder = 5.
8) 1796 ÷ 10
10) 1 7 9 6 (179
1 0
7 9
7 0
9 6
9 0
6
Quotient = 179, Remainder = 6.
07 / JULY / 2020
MATHEMATICS
Chapter 7 DIVISION
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 90, Ex No. 7G, Do No. 23 to 32.
Two of them have been done for you.
25) 5 9 3 7 ÷ 7
7) 5 9 3 7 (848
5 6
3 3
2 8
5 7
5 6
1
Quotient = 848, Remainder = 1
Verification:
Divisor X Quotient+ Remainder
7 X 848 + 1
= 5936 + 1 = 5937 = Dividend ( given)
30) 3101÷ 6
6) 3 1 0 1 (516
3 0
1 0
6
4 1
3 6
5
Quotient = 516, Remainder = 5
Verification:
Divisor X Quotient+ Remainder
6 X 516 + 5
= 3096 + 5 = 3101 = Dividend (given)
06 / JULY / 2020
MATHEMATICS
Chapter 7 DIVISION
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 90, Ex No. 7G, Do No. 13 to 22.
Two of them have been done for you.
15) 769 ÷ 8
8) 7 6 9 (96 7 2
4 9
4 8
1
Quotient = 96, Remainder= 1
Verification:
Divisor X Quotient+ Remainder
= 8 X 96 + 1
= 768 + 1 = 769= Dividend (given)
20) 6793 ÷ 7
7) 6 7 9 3 (970
6 3
4 9
4 9
0 3
0
3
Quotient = 970, Remainder = 3
Verification:
Divisor X Quotient + Remainder
7 X 970 + 3
= 6790 + 3 = 6793 = Dividend (given)
03 / JULY / 2020
MATHEMATICS
Chapter 7 DIVISION
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 90, Ex No. 7G, Do No.1to 12.
Three of them have been done for you.
1) 17 ÷ 2
2) 1 7 (8 1 6
1
Quotient = 8, Remainder = 1
Verification:
Divisor X Quotient + Remainder
= 2 X 8 + 1
= 16 + 1 = 17 = Dividend ( given )
6) 253 ÷ 7
7) 2 5 3 (36
2 1
4 3
4 2
1
Quotient = 36, Remainder = 1
Verification:
Divisor X Quotient+ Remainder
= 7 X 36 + 1
= 252 + 1= 253= Dividend ( given).
11) 777 ÷ 9
9) 7 7 7 (86
7 2
5 7
5 4
3
Quotient = 86, Remainder = 3
Verification:
Divisor X Quotient+ Remainder
= 9 X 86 + 3
= 774 + 3 = 777= Dividend (given)
02 / JULY / 2020
MATHEMATICS
Chapter 7 DIVISION
NOW WATCH THE VIDEO.
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 88, Ex No. 7F, Do No. 25 to 36.
Three of them have been done for you.
26) 799 ÷ 5
5) 7 9 9 (159
5
2 9
2 5
4 9
4 5
4
Hence, Quotient = 159, Remainder = 4
Dividend = Quotient X divisor + Remainder
= 159 X 5 + 4 = 795 + 4 = 799.
31) 699 ÷ 4
4) 6 9 9 (174
4
2 9
2 8
1 9
1 6
3
Hence, Quotient = 174, Remainder = 3
Dividend = Quotient X divisor + Remainder
= 174 X 4 + 3 = 696 + 3 = 699.
36) 9051 ÷ 7
7) 9 0 5 1 (1293
7
2 0
1 4
6 5
6 3
2 1
2 1
0
Hence, Quotient = 1293, Remainder = 0
Dividend = Quotient X divisor + Remainder
= 1293 X 7 + 0 = 9051 + 0 = 9051.
01 / JULY / 2020
MATHEMATICS
Chapter 7 DIVISION
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No.88, Ex No. 7F, Do No. 13 to 24.
Three of them have been done for you.
15) 896 ÷ 7
7) 8 9 6 (128
7
1 9
1 4
5 6
5 6
0
Hence, Quotient= 128, Remainder = 0
Dividend = Quotient X divisor + Remainder
= 128 X 7 + 0 = 896 + 0 = 896.
19) 900 ÷ 8
8) 9 0 0 (112
8
1 0
8
2 0
1 6
4
Hence, Quotient = 112, Remainder = 4
Dividend = Quotient X divisor + Remainder
= 112 X 8 + 4 = 896 + 4 = 900
23) 503 ÷ 2
2) 5 0 3 (251
4
1 0
1 0
0 3
2
1
Hence, Quotient = 251, Remainder = 1
Dividend = Quotient X divisor+ Remainder
= 251 X 2 + 1 = 502 + 1 = 503.
30 / JUNE / 2020
MATHEMATICS
Chapter 7 DIVISION
Division with Remainder
NOW WATCH THE VIDEO.
Explanation:
Divide 79 by 4
4) 7 9 (19
4
3 9
3 6
0 3
Hence, Quotient = 19, Remainder = 3.
Verification: We know that
Dividend = Quotient X divisor + Remainder
= 19 x 4 + 3 = 76 + 3 = 79.
Hence, the result is verified.
Assignment: Complete all exercises in your Mathematics-OCB
Mathematics book, Pg No. 88, Ex No.7F, Do No. 1 to 12.
Three of them have been done for you.
1) 68 ÷ 5
5) 6 8 (13
5
1 8
1 5
0 3
Hence, Quotient= 13, Remainder = 3
Dividend = Quotient X divisor + Remainder
= 13 X 5 + 3 = 65 + 3 = 68.
6) 97 ÷ 8
8) 9 7 (12
8
1 7
1 6
0 1
Hence, Quotient = 12, Remainder = 1
Dividend = Quotient X divisor + Remainder
= 12 X 8 + 1 = 96 + 1 = 97.
11) 842 ÷ 7
7) 8 4 2 (120
7
1 4
1 4
0 2
0
2
Hence, Quotient = 120, Remainder = 2.
Dividend = Quotient X divisor + Remainder
= 120 X 7 + 2= 840 + 2 = 842.
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